Question

Answer 1

Bài 1:

a: Ta có: \(-5x+12=-8\)

\(\Leftrightarrow-5x=-20\)

hay x=4

b: Ta có: \(\left(x+3\right)\left(x-4\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x+3=0\\x-4=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-3\\x=4\end{matrix}\right.\)

c: Ta có: \(\dfrac{x+5}{2}-\dfrac{3-2x}{4}=5\)

\(\Leftrightarrow2x+10-3+2x=5\)

\(\Leftrightarrow4x=-2\)

hay \(x=-\dfrac{1}{2}\)