a) \(\sqrt{\left(\sqrt{5}-3\right)^2}+\sqrt{\left(\sqrt{5}+4\right)^2}\)
\(=\left|\sqrt{5}-3\right|+\left|\sqrt{5}+4\right|\)
\(=\sqrt{5}-3+\sqrt{5}+4\)
\(=2\sqrt{5}+1\)
b) \(11\sqrt{3}+2\sqrt{12}-3\sqrt{27}+4\sqrt{75}\)
\(=11\sqrt{3}+4\sqrt{3}-9\sqrt{3}+20\sqrt{3}\)
\(=26\sqrt{3}\)
c) \(\sqrt{x^2-6x+9}+2x-1\)
\(=\sqrt{\left(x-3\right)^2}+2x-1\)
\(=x-2+2x-1\)
\(=3x-4\)
d) \(\sqrt{28+10\sqrt{3}}-\sqrt{19-8\sqrt{3}}\)
\(=\sqrt{\left(5+\sqrt{3}\right)^2}-\sqrt{\left(4-\sqrt{3}\right)^2}\)
\(=5+\sqrt{3}-4+\sqrt{3}\)
\(=2\sqrt{3}+1\)
a: Ta có: \(\sqrt{\left(\sqrt{5}-3\right)^2}+\sqrt{\left(\sqrt{5}+4\right)^2}\)
\(=3-\sqrt{5}+4+\sqrt{5}\)
=7
b: Ta có: \(11\sqrt{3}+2\sqrt{12}-3\sqrt{27}+4\sqrt{75}\)
\(=11\sqrt{3}+4\sqrt{3}-9\sqrt{3}+20\sqrt{3}\)
\(=26\sqrt{3}\)
c: Ta có: \(\sqrt{x^2-6x+9}+2x-1\)
\(=x-3+2x-1\)
=3x-4
d: Ta có: \(\sqrt{28+10\sqrt{3}}-\sqrt{19-8\sqrt{3}}\)
\(=5+\sqrt{3}-4+\sqrt{3}\)
\(=2\sqrt{3}+1\)
