Question

Answer 1

c) \(\dfrac{8^2\cdot4^5}{2^{20}}=\dfrac{2^6\cdot2^{10}}{2^{20}}=\dfrac{2^{16}}{2^{20}}=\dfrac{1}{2^4}=\dfrac{1}{16}\)

k) \(\left(-\dfrac{9}{3}\right)^4:2^4=\left(-3:2\right)^4=\left(\dfrac{-3}{2}\right)^4=\dfrac{81}{16}\)