a) \(\left(0.25\right)^3\cdot32=\left(\dfrac{1}{5}\right)^3\cdot32=\dfrac{1}{125}\cdot32=\dfrac{32}{125}\)
b) \(\left(-0.125\right)^3\cdot80^2=\left(-\dfrac{1}{8}\right)^3\cdot80^2=\dfrac{-1}{8^3}\cdot8^2\cdot10^2=\dfrac{-1}{8}\cdot10^2=\dfrac{-100}{8}=\dfrac{-25}{2}\)
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