Question

Answer 1

Ta có

\(\dfrac{x}{2}=\dfrac{y}{3}\Rightarrow\dfrac{x}{y}=\dfrac{2}{3}\)

\(\Rightarrow x=\dfrac{2}{3}y\)

Mà \(x.y=96\Rightarrow\dfrac{2}{3}y.y=96\Leftrightarrow\dfrac{2}{3}y^2=96\Leftrightarrow y^2=144\)

=> y = 12 => x = 8

Answer 2

đề bài bảo tìm x thì tôi tìm x nhé :D

Answer 3

Ta co: \(\dfrac{x}{2}.\dfrac{x}{2}=\dfrac{y}{5}.\dfrac{x}{2}\)

\(\left(\dfrac{x}{2}\right)^{^2}=\dfrac{y.x}{5.2}=\dfrac{10}{10}=1\)

\(\Rightarrow\left[{}\begin{matrix}\dfrac{x}{2}=1\\\dfrac{x}{2}=-1\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=2\\x=-2\end{matrix}\right.\)

TH1: \(\dfrac{2}{2}=\dfrac{y}{5}\)

\(\Rightarrow y=5\)

TH2: \(\dfrac{-2}{2}=\dfrac{y}{5}\)

\(\Rightarrow y=-5\)