a,\(\frac{x}{y}=\frac{7}{3}\Rightarrow\frac{x}{7}=\frac{y}{3}\Rightarrow\frac{5x}{35}=\frac{2y}{6}=\frac{5x-2y}{35-6}=\frac{87}{29}=3\)
=> x = 21; y = 9
b, \(\frac{x}{19}=\frac{y}{21}\Rightarrow\frac{2x}{38}=\frac{y}{21}=\frac{2x-y}{38-21}=\frac{34}{17}=2\)
=> x = 38; y = 42