Vì ƯCLN ( x,y ) = 12 nên :
x = 12m (m , n) = 1 ; m,n khác 0
y = 12n
x + y = 12m + 12n 84
x + y = 12 ( m + n ) = 84
=> m + n = 84 : 12 = 7
Ta lập bảng ( x > y ) :
m | 6 | 5 | 4 |
n | 1 | 2 | 3 |
x | 72 | 60 | 48 |
y | 12 | 24 | 36 |
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Vì ƯCLN ( x,y ) = 12 nên :
x = 12m (m , n) = 1 ; m,n khác 0
y = 12n
x + y = 12m + 12n 84
x + y = 12 ( m + n ) = 84
=> m + n = 84 : 12 = 7
Ta lập bảng ( x > y ) :
m | 6 | 5 | 4 |
n | 1 | 2 | 3 |
x | 72 | 60 | 48 |
y | 12 | 24 | 36 |
a) a-b=84 va UCLN cua a,b=12
b) a*b=864 va UCLN cua a,b=6
c) a+b=432 va BCNN cua a,b=210
tim 2 so tu nhien biet hieu cua chung bang 84 va UCLN bang 12
tim 2so tu nhien biet hieu cua chung =84 va UCLN cua chung =12
tim hai so tu nhien khi biet tong cua chung la 84 va UCLN cua chung la 12
1,tim 2 so tu nhien biet tong chung = 66 UCLN=6 co 1 so chia het cho 5
2,tim 2 so tu nhien biet hieu chung = 84 UCLN = 12
3,tim 2 so tu nhien biet tich = 864 UCLN=6
4,cho 3n+1 va 5n+4 la 2 so nguyen to cung nhau tim UCLN cua 3n+1 va 5n+4
5,cho a=123456789;b=987654321 . Tim UCLN cua a va b
UCLN cua (24 ,84 va 180 )
tim x va y biết
x+y=x nhân y = x:y
Biet rang : BCNN(a,b).UCLN(a,b)
a, BCNN cua hai so la 600, UCLN cua chung nho hon 10 lan BCNN. So thu 1 la 120, tim so thu 2.
b, UCLN cua hai so la 12, BCNN cua chung lon gap 6 lan UCLN . So t 1 la 24, tim so t 2
c, Tong cua hai so bang 60, tong giua UCLN va BCNN cua chung la 84. Tim hai so do.
tim x dua vao quan he uoc boi:
tim so tu nhien x sao cho x-1 la uoc cua 12
tim so tu nhien x sao cho 2x+1 la uoc cua 28
tim so tu nhien x sao cho x+15 la boi cua x+3
tim cac so nguyen x,y sao cho (x+1)(y-2)=3
tim so nguyen x sao cho(x+2).(y-1)=2
tim so nguyen to x vua la uoc cua 275 vua la uoc cua 180
tim so nguyen to x,y biet x+y=12 va UCLL (x:y)=5
tim so tu nhien x,y biet x+y=32 va UCLL (x:y)=8
tim so tu nhien x biet x chia het cho10; xchia het cho12; x chia het cho15 va 100<x<150
tim so x nho nhat khac 0b biet x chia het cho 24 va 30
40 chia het cho x . 56 chia het cho x va x>6