Question

\(x\left(x-4\right)-\)(x mũ 2-8)=0

 

Answer 1

`x(x-4)-(x^2-8)=0`

`<=>x^2-4x-x^2+8=0`

`<=>-4x=-8`

`<=>x=2` 

Vậy `S={2}`

Answer 2

`x(x-4)-(x^2-8)=0`

`<=> x^2 - 4x -x^2+8=0`

`<=> -4x=-8`

`<=>x=2`