\(\left(x+3\right)^2=16\)
\(\left(x+3\right)^2=4^2\)
\(x+3=4\)
\(x=4-3\)
\(x=1\)
Ta có:
(x + 3)^2 = 16
(x + 3)^2 = 4^2
=> x + 3 = 4
x = 4 - 3
x = 1
Vậy x = 1
\(\left(x+3\right)^2=16\)
\(\Rightarrow\left(x+3\right)^2=4^2\)
\(\Rightarrow\orbr{\begin{cases}x+3=4\\x+3=-4\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=1\\x=-7\end{cases}}\)
tíc mình nha
\(\left(x+3\right)^2=16\)
\(\Rightarrow\orbr{\begin{cases}\left(x+3\right)^2=4^2\\\left(x+3\right)^2=\left(-4\right)^2\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x+3=4\\x+3=\left(-4\right)\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=1\\x=\left(-7\right)\end{cases}}\)
Ta có
kết quả là:
= 1
nha bn
vì: ( 1 + 3 )2 = 42 = 4 x 4 = 16
\(\left(x+3\right)^2=16\)
\(\Rightarrow\left(x+3\right)^2=\orbr{\begin{cases}\left(-4\right)^2\\4^2\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x+3=-4\\x+3=4\end{cases}}\)
\(\orbr{\begin{cases}\left(-4\right)-3=x\\4-3=x\end{cases}}\)
\(\orbr{\begin{cases}x=-7\\x=1\end{cases}}\)