Question

\(x+30\%.x=-1,31\)

nhờ các cụ giải ai giải dc thề cho 1 k

Answer 1

\(x+30\%.x=-1,31\Leftrightarrow100x+30x=131\Leftrightarrow130x=131\Leftrightarrow x=\frac{131}{130}=1\frac{1}{130}\)

Answer 2

âm131/130

Answer 3

ai chả bt giải ra

Answer 4

nhầm nhé làm lại \(x+30\%x=-1,31\Leftrightarrow100x+30x=-131\)

                       \(\Leftrightarrow130x=-131\Leftrightarrow x=-\frac{131}{130}\)

Answer 5

bạn làm gần đúng mình cũng k nha

Answer 6

\(x+30\%.x=-1,31\)

\(x+\frac{3}{10}.x=\frac{-131}{100}\)

\(x.1+\frac{3}{10}.x=\frac{-131}{100}\)

\(x.\left(1+\frac{3}{10}\right)=\frac{-131}{100}\)

\(x.\frac{13}{10}=\frac{-131}{100}\)

\(x=\frac{-131}{100}:\frac{13}{10}\)

\(x=\frac{-131}{130}\)

Answer 7

\(x+30\%x=-1,31\)

\(=>100x+30x=131\)

\(=>130x=131\)

\(=>x=\frac{131}{130}=1\frac{1}{130}\)

Answer 8

co lam thi moi co an   ok

Answer 9

tớ  mx lớp 6

Answer 10

CAC BN GIOI GE

Answer 11

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Answer 12

\(x+30\%x=-1,31\)

\(< =>x.\frac{100}{100}+x.\frac{30}{100}=-1,31\)

\(< =>x\left(\frac{100}{100}+\frac{30}{100}=-1,31\right)\)

\(< =>x.\frac{130}{100}=x.\frac{13}{10}=-1,31\)

\(< =>13x=-13,1\)

\(< =>130x=-131\)

\(< =>x=-\frac{131}{130}\)

Answer 13

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