Question

(x3-3x2+2x-6):(x-3)

(x3-8):(x-2)

Answer 1

Lời giải:

$(x^3-3x^2+2x-6):(x-3)=[x(x-3)+2(x-3)]:(x-3)$

$=(x-3)(x+2):(x-3)=x+2$

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$(x^3-8):(x-2)=(x-2)(x^2+2x+4):(x-2)=x^2+2x+4$