Question

x²+6x-x-6=0

x²+3x-2x-6=0

Answer 1

\(x^2+6x-x-6=0\)

\(x\left(x-1\right)+6\left(x-1\right)=0\)

\(\left(x-1\right)\left(x+6\right)=0\)

\(\orbr{\begin{cases}x-1=0\Rightarrow x=1\\x+6=0\Rightarrow x=-6\end{cases}}\)

Answer 2

(x^2-x)+(6x-6)=0

x(x-1)+6(x-1)=0

(x-1)(x+6)=0

x=1 và x=-6

Answer 3

\(x^2+6x-x-6=0\)

\(=x\left(x+6\right)-\left(x+6\right)=0\)

\(=\left(x-1\right)\left(x+6\right)=0\)

\(\Rightarrow\orbr{\begin{cases}x-1=0\\x+6=0\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=1\\x=-6\end{cases}}\)

Answer 4

\(x^2+6x-x-6=0\)

\(=>x\left(x-1\right)+6\left(x-1\right)=0\)

\(=>\left(x-1\right)\left(x+6\right)=0\)

\(=>\orbr{\begin{cases}x-1=0\\x+6=0\end{cases}=>\orbr{\begin{cases}x=1\\x=-6\end{cases}}}\)