Question

x^2 (x-3) + 12-4x

Answer 1

\(x^2 (x-3) + 12-4x\)

\(= x^2 (x-3)-4-(x-3)\)

\(= (x^2-4) (x-3)\)

\(= (x^2-2^2) (x-3)\)

\(= (x-2) (x+2) (x-3)\)

vậy \(x^2 (x-3) +12-4x=0\)

vậy \(x=2 hoặc x=-2 hoặc x=3\)

Answer 2

\(x^2\left(x-3\right)+12-4x\)

\(\Leftrightarrow x^3-3x^2+12-4x\)