Question

x²-\(\dfrac{1}{49}\)=0

64-0,25x²=0

 

Answer 1

\(x^2-\dfrac{1}{49}=0\\ \Leftrightarrow x^2=\dfrac{1}{49}=\left(\dfrac{1}{7}\right)^2=\left(-\dfrac{1}{7}\right)^2\\\Rightarrow\left[{}\begin{matrix}x=\dfrac{1}{7}\\x=-\dfrac{1}{7}\end{matrix}\right.\\ 64-0,25x^2\\ \Leftrightarrow0,25x^2=64\\ x^2=\dfrac{64}{0,25}=256=16^2=\left(-16\right)^2\\ \Rightarrow\left[{}\begin{matrix}x=16\\x=-16\end{matrix}\right.\)

Answer 2

\(x^2-\dfrac{1}{49}=0\\ \Rightarrow x^2=\dfrac{1}{49}\\ \Rightarrow x^2=\pm\dfrac{1}{7}\)

 

\(64-0,25x^2=0\\ \Rightarrow\left(0,5x\right)^2=64\\ \Rightarrow\left(0,5x\right)=\pm8\\ \Rightarrow x=\pm16\)