=> x2 - 9 - 5x - 15 = 0
=> x2 - 5x - 24 = 0
=> x2 - 8x + 3x - 24 = 0
=> x(x - 8) + 3(x - 8) = 0
=> (x + 3)(x - 8) = 0
=> x + 3 = 0 => x = -3
hoặc x - 8 = 0 => x = 8
Vậy x = -3 ; x = 8
x2-9=5x-15
\(\Leftrightarrow\) (x+3)(x-3)-5(x+3)=0
\(\Leftrightarrow\) (x+3)(x-3-5)=0
\(\Leftrightarrow\) (x+3)(x-8)=0
\(\Leftrightarrow\) x=-3 hoặc x=8
Vậy...