Question

(x^2 + 1)(x^3 - 8) = 0

Answer 1

`(x^2 + 1 ) ( x^3 - 8 ) = 0`

Vì `x^2 + 1 > 0`

`=> x^3 - 8 = 0`

`=> x^3 = 8`

`=> x^3 = 2^3`

`=>x =2`

Vậy `x = 2`