\(\left(x+1\right)^2+7=\left(x+1\right).\left(x+1\right)+7\)
mà \(x+1⋮x+1\Rightarrow\left(x+1\right).\left(x+1\right)⋮x+1\)
\(\Rightarrow7⋮x+1\)
\(\Rightarrow x+1\inƯ\left(7\right)\)
\(\Rightarrow x+1\in\hept{ }1;-1;7;-7\)
TH1: \(x+1=1\Rightarrow x=1-1=0\)
TH2: \(x+1=-1\Rightarrow x=-1-1=-2\)
TH3: \(x+1=7\Rightarrow x=7-1=6\)
TH4: \(x+1=-7\Rightarrow x=-7-1=-8\)
Vậy x = .....
Nhớ k cho mình nhé! Thank you!!!