Question

(x+1/20)+(x+1/30)+(x+1/42)+(x+1/56)=1/8

Answer 1

\(\left(x+\frac{1}{20}\right)+\left(x+\frac{1}{30}\right)+\left(x+\frac{1}{42}\right)+\left(x+\frac{1}{56}\right)=\frac{1}{8}\)

Ta mở ngoặc rồi tính như sau:

\(x+\frac{1}{20}+x+\frac{1}{30}+x+\frac{1}{42}+x+\frac{1}{56}=\frac{1}{8}\)

\(\Leftrightarrow4x+\left(\frac{1}{20}+\frac{1}{30}+\frac{1}{42}+\frac{1}{56}\right)=\frac{1}{8}\)

\(\Leftrightarrow4x+\frac{1}{8}=\frac{1}{8}\)

\(\Leftrightarrow4x=0\)

Vậy \(x=0\)

Answer 2

thaks bạn nha