Câu hỏi của Tăng Hiếu

Question

(x+1)^2-(x+1)(x-1)=0

Tăng Hiếu · Accepted Answer

giúp mik với Câu trả lời: giúp mik với

Shiba Inu · Answer

(x + 1)2 - (x + 1)(x - 1) = 0$\Rightarrow$ x2 + 2x + 1 - x2 + 1 = 0$\Rightarrow$ 2x + 2 = 0$\Rightarrow$ 2x = - 2$\Rightarrow$ x = - 1Vậy x = - 1Câu trả lời:     (x + 1)2 - (x + 1)(x - 1) = 0$\Rightarrow$ x2 + 2x + 1 - x2 + 1 = 0$\Rightarrow$ 2x + 2 = 0$\Rightarrow$ 2x = - 2$\Rightarrow$ x = - 1Vậy x = - 1

꧁_͏ͥ͏_͏ͣ͏_͏ͫ͏ ¡亗ᵛᶰシ๖ۣۜ... · Answer

$\left(x+1\right)^2-\left(x+1\right).\left(x-1\right)=0$ $\Rightarrow\left(x+1\right).\left(x+1\right)-\left(x+1\right).\left(x-1\right)=0$ $\Rightarrow\left(x+1\right).\left[\left(x+1\right)-\left(x-1\right)\right]=0$ $\Rightarrow\left(x+1\right).\left[x+1-x+1\right]=0$ $\Rightarrow\left(x+1\right).\left[\left(x-x\right)+\left(1+1\right)\right]=0$ $\Rightarrow\left(x+1\right).\left[0+2\right]=0$ $\Rightarrow\left(x+1\right).2=0$ $\Rightarrow x+1=0:2$ $\Rightarrow x+1=0$ $\Rightarrow x=0-1$ $\Rightarrow x=-1$Câu trả lời: $\left(x+1\right)^2-\left(x+1\right).\left(x-1\right)=0$ $\Rightarrow\left(x+1\right).\left(x+1\right)-\left(x+1\right).\left(x-1\right)=0$ $\Rightarrow\left(x+1\right).\left[\left(x+1\right)-\left(x-1\right)\right]=0$ $\Rightarrow\left(x+1\right).\left[x+1-x+1\right]=0$ $\Rightarrow\left(x+1\right).\left[\left(x-x\right)+\left(1+1\right)\right]=0$ $\Rightarrow\left(x+1\right).\left[0+2\right]=0$ $\Rightarrow\left(x+1\right).2=0$ $\Rightarrow x+1=0:2$ $\Rightarrow x+1=0$ $\Rightarrow x=0-1$ $\Rightarrow x=-1$

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