VT >0 => VP > 0 => x >0
số dấu | | là (397 - 1): 4 + 1 = 100
\(\Rightarrow100x+\left(\frac{1}{1.5}+\frac{1}{5.9}+...+\frac{1}{397.401}\right)=101x\)
\(\Rightarrow x=\left(\frac{1}{1.5}+\frac{1}{5.9}+...+\frac{1}{397.401}\right)\)
\(\Rightarrow4x=1-\frac{1}{401}\)
\(x=\frac{100}{401}\)(tm)
Tim x biet:
|x+1/1.5|+|x+1/5.9|+|x+1/9.13|+...+|x+1/397.401|=101
tìm x biết; /x+1:(1.5)/+ /x+1: (5.9)/+........+ /x +1: (397.401)/=101x
\(\left|x+\frac{1}{1.5}\right|+\left|x+\frac{1}{5.9}\right|+...+\left|x+\frac{1}{397.401}\right|=101x\)
d, \(\frac{1}{1.5}+\frac{1}{5.9}+...........+\frac{1}{397.401}< \frac{1}{4}\)
A ) / X + 2 / + / X + / + / X + \(\frac{1}{2}\)/ = 4X
b ) / x + 1,1 / + / x + 1,2 / + / x + 1,3 / + / x + 1,4 / = 5x
c ) / x + \(\frac{1}{1.3}\)/ + / x + \(\frac{1}{3.5}\)/ + / x +\(\frac{1}{5.7}\) / + ........ + / x + \(\frac{1}{97.99}\)/ = 50x
d ) / x + \(\frac{1}{1.5}\)/ + / x + \(\frac{1}{5.9}\)/ + / x + \(\frac{1}{9.13}\)/ + ......... + / x + \(\frac{1}{397.401}\)/ = 101x
Tìm x biết
4/1.5 + 4/5.9+... +4/97.101 = 2x+5/101
Tìm x thỏa mãn
a, \(\frac{1}{1.4}+\frac{1}{4.7}+...+\frac{1}{97.100}=|\frac{x}{3}|\)
b, \(\frac{4}{1.5}+\frac{4}{5.9}+...+\frac{4}{97.101}=|\frac{5x-4}{101}|\)
c,\(\left(1-\frac{1}{2}\right)\left(1-\frac{1}{3}\right)\left(1-\frac{1}{4}\right)...\left(1-\frac{1}{100}\right)=|x-1\frac{99}{100}|\)
Tìm x:
\(\frac{x}{1.5}+\frac{x}{5.9}+\frac{x}{9.13}+...+\frac{x}{53.57}=\frac{56}{57}\)
tinh M=-1/(1.5)-1/(5.9)-.....-1/((n+4).n)