Bổ sung: \(x,y\in \mathbb{Z}\)
\(x\left(x+1\right)+y=2\\ \Rightarrow x\left(y+1\right)+\left(y+1\right)=3\\ \Rightarrow\left(x+1\right)\left(y+1\right)=3=3.1=\left(-3\right)\left(-1\right)\)
\(x+1\) | 1 | 3 | -1 | -3 |
\(y+1\) | 3 | 1 | -3 | -1 |
\(x\) | 0 | 2 | -2 | -4 |
\(y\) | 2 | 0 | -4 | -2 |