`x xx 1/5 =1-2/3`
`=> x xx 1/5= 3/3-2/3`
`=> x xx 1/5= 1/3`
`=>x=1/3 :1/5`
`=>x=1/3 xx 5`
`=>x=5/3`
Vậy `x=5/3`
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`x : 3/4 = (2/3+1/3) : 3/4`
`=> x : 3/4 = 3/3 : 3/4`
`=> x : 3/4 = 1 xx 4/3`
`=> x: 3/4 =4/3`
`=> x= 4/3 xx 3/4`
`=> x= 12/12=1`
Vậy `x=1`
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\(x\times\dfrac{1}{5}=1-\dfrac{2}{3}\)
\(x\times\dfrac{1}{5}=\dfrac{3}{3}-\dfrac{2}{3}\)
\(x\times\dfrac{1}{5}=\dfrac{1}{3}\)
\(x=\dfrac{1}{3}:\dfrac{1}{5}\)
\(x=\dfrac{1}{3}\times5=\dfrac{5}{3}\)
\(Vậy:x=\dfrac{5}{3}\)
\(x:\dfrac{3}{4}=\left(\dfrac{2}{3}+\dfrac{1}{3}\right):\dfrac{3}{4}\)
\(x:\dfrac{3}{4}=1:\dfrac{3}{4}\)
\(x=1\)
\(Vậy:x=1\)
#Toru
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