Question

X-|x-1| (x > hoặc = 1)

Answer 1

`@TH1:x-1 >= 0<=>x > 1=>|x-1|=x-1`

Có: `x-(x-1)=x-x+1=1`

`@TH2:x-1 < 0<=>x < 1=>|x-1|=1-x`

Có: `x-(1-x)=x-1+x=2x-1`

Answer 2

Ta có x >= 1 

\(=x-\left|x-1\right|=x-\left(x-1\right)=x-x+1=1\)

Answer 3

Với x >= 1, ta có |x - 1| = x - 1

x - |x - 1| = x - (x - 1) = x - x + 1 = 1