( x - 7 ) . ( 2x - 8 ) = 0
=> x - 7 = 0 hoặc 2x - 8 = 0
x = 0 + 7 2x = 0 + 8
x = 7 2x = 8
x = 8 : 2
x = 4
Vậy x thuộc { 4; 7 }
\(\orbr{\begin{cases}x-7=0\\2x-8=0\end{cases}}\)\(\Leftrightarrow\)\(\orbr{\begin{cases}x=7\\x=4\end{cases}}\)
( x - 7 ) . ( 2x - 8 ) = 0
=> x - 7 = 0 hoặc 2x - 8 = 0
x = 0 + 7 2x = 0 + 8
x = 7 2x = 8
x = 8 : 2
x = 4
Vậy x thuộc { 4; 7 }
\(\orbr{\begin{cases}x-7=0\\2x-8=0\end{cases}}\)\(\Leftrightarrow\)\(\orbr{\begin{cases}x=7\\x=4\end{cases}}\)
1.
a.|2x+4|+|4x+8|=0|2x+4|+|4x+8|=0
b.|x−5|+|x−7|=0|x−5|+|x−7|=0
c.|x+8|−|2x+2|=0
tìm STN x
2x + 69 . 2 = 69 . 4
2x - 12 - x = 0
(x-7) . (2x - 8) = 0
tim x biet:a.2x^2-1=17/8;b.(2x-0,05)(x+3)>0;c.(7-x)(x+19)>0
(x-7)x(2x-8)=0
Bài 2: Tìm x:
a) 128 – 2x = -8 – x
b) x – (-15).2 = 55 – 7.(-3)
c) 66 – [5 – (-x)] = 169
d) (8 – 2x).(8 + x) = 0
e) 7 – [x2 + (-9)] = -20
mn ơi giúp mình
đang gấp ạ
xin cảm ơn
(2x-5)3=152-4.52
(x-2)(15-3x)=0
(x-5)-(2x+7)= -8
Tìm x : 2x - 12 - x =0
( x - 7) . ( 2x - 8) = 0
(x-7).(2x-8)=0. Tìm x
a,(x-7).(2x-8)=0
b,(x-1)^6=(x-1)^8
(x-7).(2x-8)=0