giải phương trình sau
1/ ( x-1) (2x+1) =0
2/ x (2x-1) (3x+15) =0
3/ (2x-6) (3x+4) x=0
4/ (2x-10)(x^2+1)=0
5/ (x^2+3) (2x-1) =0
6/ (3x-1) (2x^2 +1)=0
Tìm x, biết:
1) 2x . (x-5) -x . (2x-4) = 15
2) (x+1) . (x+2) - (x+4) . (x+3) = 6
3) 4x2 - 4x+5 - x . (4x-3) = 1-2x
4) (x+3) . (2x+1) - 2x2 = 4x-5
5) -4 . (2x-8) + (2x-1) . (4x+3) = 0
6) -3 . (x-2) + 4 . (2x-6) - 7 . (x-9)= 5 . (3-2)
7) (x-2) . (x+2) -2 . (x-4) = 10. 3x
8) 15x . (x-2) - (5x-1) . (3x + 1) = 6
9) (2x+4) . (x-3) - x . (2x-10) =15-20x
10) (4x-2) . (3x+4) - (2x-1) . (6x+5) = 100
HEPL ME !!! Cần làm gấp những bài này, ai lm dc mk tick cho ng đó nha !!! THANK YOU !!!!
a, x+5/4-2x-3/3=6x-1/3+2x-1/12
b,5x-1/10+ 2x+3/6=x-8/15-x/30
các bn giúp mk vs, càng nhanh càng tốt
thank's
a, x^2-36/2x+10*3/6-x
b,5x-15/4x+4:x^2-9/x^2+2x+1
c,3-2x/ x^2-9 + 1/2x-6
d, -5/4+2y + y-2/2y+y^2
a)\(\frac{2x+4}{10}+\frac{2-x}{15}\)
b)\(\frac{3x}{10}+\frac{2x-1}{15}+\frac{2-x}{20}\)
c)\(\frac{x+1}{2x-2}+\frac{x^2+3}{2-2x^2}\)
d)\(\frac{1-2x}{2x}+\frac{2x}{2x-1}+\frac{1}{2x-2x^2}\)
e)\(\frac{x}{xy-y^2}+\frac{2x-y}{xy-x^2}\)
f)\(\frac{x^2}{x^2-4x}+\frac{6}{6-3x}+\frac{1}{x+2}\)
\(\frac{2x+9}{\left(x+1\right)\left(x+8\right)}-\frac{2x+15}{\left(x+8\right)\left(x+7\right)}+\frac{2x+10}{\left(x+7\right)\left(x+3\right)}=\frac{4}{3}\)
5(2x - 3)2 - 5(x+1)2 - 15(x+4)(x-4) = -10
tìm x biết
a) 5x(2x-7)+2x(8-5x)=5
b)(3x-5)(7-5x)-(5x+2)(2-3x)=4
c)5(2x-3)^2-5(x+1)^2-15(x+4)(x-4)=-10
d) 5x(x-3)(x+3)-(2x-3)^2 -5(x+2)^3+34x(x+2)=1
giai phuong trinh
(2x + 1)(x + 1)^2 (2x + 3) = 18
(x^2 - 6x + 9)^2 - 15(x^2 - 6x + 10) = 1
gi¶i chi tiÕt giumg mik nha
