Question

x-2xy+y=0

tìm x,y

Answer 1

x - 2xy + y = 0

=> 2x - 4xy + 2y = 0

=> 2x(1 - 2y) - 1 + 2y = -1

=> 2x(1 - 2y) - (1 - 2y) = -1

=> (2x - 1)(1 - 2y) = -1

lập bảng...

Answer 2

     Trả lời:
x‐2xy+y=0
=> x‐(2xy‐y)=0
=> x‐ y(2x‐1)=0
=> (2x‐2y)(2x‐1)=0
=> ( 2x‐1) ‐2y(2x‐1)=‐1
=> (2x‐1)(1‐2y)=‐1
=> ( 2x‐1 ; 1‐2y ) = ( ‐1 ;1 ﴿ ; ﴾1;‐1 )
=> (x;y)=( 0 ; 0 ) ; ( 1;1)

HOK TỐT

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Answer 3

Ta có : x - 2xy + y  =0

<=> x . ( 1 - 2y ) = -y <=> x = \(\frac{-y}{1-2y}\)

Để x ; y nguyên => \(\frac{-y}{1-2y}\)nguyên 

=> \(\frac{y}{2y-1}\)=> y = 1 ; x = 1

Vậy x = 1 ; y = 1