(x -2\3 ) * 3 =3\4
= \(\left(x-\frac{2}{3}\right).3=\frac{3}{4}\)
= \(\left(x-\frac{2}{3}\right)=\frac{3}{4}:3=\frac{1}{4}\)
= \(\left(x-\frac{2}{3}\right)=\frac{1}{4}\)
=> x = \(\frac{1}{4}+\frac{2}{3}=\frac{11}{12}\)
=> x = \(\frac{11}{12}\)
\(\left(x-\frac{2}{3}\right)\times3=\frac{3}{4}\)
\(x-\frac{2}{3}=\frac{3}{4}:3\)
\(x-\frac{2}{3}=\frac{1}{4}\)
\(x=\frac{1}{4}+\frac{2}{3}\)
\(x=\frac{11}{12}\)
Vậy \(x=\frac{11}{12}\)
( x - \(\frac{2}{3}\) ) * 3 = \(\frac{3}{4}\)
x - \(\frac{2}{3}\) = \(\frac{3}{4}\) : 3
x - \(\frac{2}{3}\) = \(\frac{1}{4}\)
x = \(\frac{1}{4}\) + \(\frac{2}{3}\)
x = \(\frac{11}{12}\)
(\(x\)-\(\frac{2}{3}\))x3=\(\frac{3}{4}\)
(\(x\)-\(\frac{2}{3}\))=\(\frac{3}{4}\)x3
\(x\)-\(\frac{2}{3}\)=\(\frac{9}{4}\)
\(x\)=\(\frac{35}{12}\)