Question

(x-2)(3-2x)=x^2-4x+4

Answer 1

(x-2)(3-2x)=x²-4x+4

=>(x-2)(3-2x)=(x-2)²

=>(x-2)(3-2x)-(x-2)(x-2)=0

=>(x-2)[(3-2x)-(x-2)=0

=>(x-2)(-3x+5)=0

=>x-2=0 hoặc -3x+5=0

=>x=2 hoặc x=5/3

Answer 2

    `( x - 2 ) ( 3 - 2x ) = x^2 - 4x + 4`

`<=> ( x - 2 ) ( 3 - 2x ) - ( x - 2 )^2 = 0`

`<=> ( x - 2 ) ( 3 - 2x - x + 2 ) = 0`

`<=> ( x - 2 ) ( 5 - 3x ) = 0`

`<=>` $\left[\begin{matrix} x - 2 = 0\\ 5 - 3x = 0\end{matrix}\right.$

`<=>` $\left[\begin{matrix} x = 2\\ x = \dfrac{5}{3}\end{matrix}\right.$

Vậy `S = { 2 ; 5 / 3 }`