Question

(x-2)(2x-1)=5(2-x)
Mik cần liền ạ

Answer 1

\(\left(x-2\right)\left(2x-1\right)=5\left(2-x\right)\)

\(\Leftrightarrow\left(x-2\right)\left(2x-1\right)=-5\left(x-2\right)\)

\(\Leftrightarrow\left(x-2\right)\left(2x-1\right)+5\left(x-2\right)=0\)

\(\Leftrightarrow\left(x-2\right)\left(2x-1+5\right)=0\)

\(\Leftrightarrow\left(x-2\right)\left(2x+4\right)=0\)

\(\Leftrightarrow2\left(x-2\right)\left(x+2\right)=0\)

\(\Leftrightarrow x-2=0\) hay \(x+2=0\)

\(\Leftrightarrow x=2\) hay \(x=-2\)

-Vậy \(S=\left\{\pm2\right\}\)

Answer 2

<=> (x-2) (2x-1) = 5(2-x) 
<=> (x-2) (2x-1) + 5(x-2 ) = 0
<=> (x-2)(2x-1+5) = 0
<=> x+2 = 0 hoặc 2x+4=0
       x=-2                2x = -4
                                x=-2