Question

x^​2​=1/16

​x³.x²​=32/243

​(x²)²=81/16

Answer 1

\(x^2=\frac{1}{16}=\left(\frac{1}{4}\right)^1=\left(-\frac{1}{4}\right)^2\)

Vậy có 2 ngiệm x

TH1: \(x=\frac{1}{4}\)

TH2: \(x=-\frac{1}{4}\)

Answer 2

x²=1/16
=>x=1/4; x=-1/4
x⁵=(2/3)⁵
=>x=2/3
x⁴=(3/2)⁴
=>x=3/2; x=-3/2

Answer 3

a)\(1\cdot x^2=\frac{1}{16}\)\(\Rightarrow x^2=\frac{1}{16}\)\(\Rightarrow x^2=\left(\frac{1}{4}\right)^2=\left(-\frac{1}{4}\right)^2\)

Vậy \(x=\frac{1}{4}\)hoặc \(x=-\frac{1}{4}\)

b)\(x^3\cdot x^2=\frac{32}{243}\)

\(\Rightarrow x^5=\frac{32}{243}\)

\(\Rightarrow x^5=\left(\frac{2}{3}\right)^5\)

\(\Rightarrow x=\frac{2}{3}\)

c) \(\left(x^2\right)^2=\frac{81}{16}\)

\(x^4=\frac{81}{16}\)

\(x^4=\left(\frac{3}{2}\right)^4=\left(-\frac{3}{2}\right)^4\)

Vậy \(x=1\frac{1}{2}\)hoặc \(x=-1\frac{1}{2}\)