\(\left(x-1\right)\left(x+2\right)-x-2=0\)
\(\Leftrightarrow\left(x-1\right)\left(x+2\right)-\left(x+2\right)=0\)
\(\Leftrightarrow\left(x+2\right)\left(x-2\right)=0\)
\(\rightarrow\orbr{\begin{cases}x+2=0\\x-2=0\end{cases}\leftrightarrow\orbr{\begin{cases}x=-2\\x=2\end{cases}}}\)
tìm x: part 1 : a,(x^3)^2-(x+1)(x-1)=1 b,(x-2)^2-3(x-2)=0 c,(x+2)(x^2-2x+4)-x(x^2+2)=15 d,(x+1)^2-(x+1)(x-2)=0 e,4x(x-2017)-x+2017=0 f,(x+4)^2-16=0 part 2: a,x^3+27+(x+3)(x-9)=0 b,(2x-1)^2-4x^2+1=0 c,2(x-3)+x^2-3x=0 d,x^2-2x+1=6x-6 e,x^3-9x=0
Bài 2: Tìm x
a) (x-2)2-(2x+3)2=0 d) x2.(x+1)-x.(x+1)+x.(x-1)=0
b) 9.(2x+1)2-4.(x+1)2=0 e) (x-2)2-(x-2).(x+2)=0
c) x3-6x2+9x=0 g) x4-2x2+1=0
h) 4x2+y2-20x-2y+26=0 i) x2-2x+5+y2-4y=0
Bài 2: Tìm x
a) (x-2)2-(2x+3)2=0 d) x2.(x+1)-x.(x+1)+x.(x-1)=0
b) 9.(2x+1)2-4.(x+1)2=0 e) (x-2)2-(x-2).(x+2)=0
Giải phương trình
a) \(x^2-2x+1=0\)
b)\(1+3x+3x^2+x=0\)
c)\(x+x^4=0\)
d)\(x^3-3x^2+3x-1+x\left(x^2-x\right)=0\)
e)\(x^2+x-12=0\)
g)\(6x^2-11x-10=0\)
1) x^2-25+2(x+5)=0
2) x(x-1)+x-1=0
3) (3x-2)^2-(x+2)^2=0
4) 2(x-2)-x^2+4x-4=0
5) 2(x^2+8x+16)-x^2+4=0
Bài 2: Tìm x
a) (x-2)2-(2x+3)2=0
b) 9.(2x+1)2-4.(x+1)2=0
c) x3-6x2+9x=0
d) x2.(x+1)-x.(x+1)+x.(x-1)=0
Tìm x biết:
1> (x+1)^2-(x+2)^2=3
2> (x-1)(x+1)-(x-3)^2=0
3> (x+1)^3-x^2(x+2)-(x-1)^2=0
4> (x+1)(x^2-x+1)-x^2(x+2)+2(x+3)^2=0
Tìm x
a) 4x(x + 1) = 8(x + 1)
b) x(x – 1) – 2(1 – x) = 0
c) 5x(x – 2) – (2 – x) = 0
d) 5x(x – 200) – x + 200 = 0
e) x3 + 4x = 0
f) (x + 1) = (x + 1)2
tìm x bt a) x^3=x^5 b) 4x.(x+1)=(x+1) c) x.(x-1)-2(1-x)=0 d) 2x.(x-2)-(2-x)^2 e) (x-3)^2+3-x=0 f) 5x.(x-2)-(2-x)=0
Phương trình \(x^2-x-2=0\) được biến thành phương trình tích là:
A. \(x^2-x=2\)
B. (x-2)(x+1)= 0
C. (x+2)(x+1) =0
D. (x-2)(x-1)= 0