Question

X-1/3+X-3/4=2 

lưu ý là X-1 tất cả trên 3 và X-3 tất cả trên 4 

Answer 1

Bài làm:

Ta có: \(\frac{x-1}{3}+\frac{x-3}{4}=2\)

\(\Leftrightarrow\left(\frac{x}{3}+\frac{x}{4}\right)=2+\frac{1}{3}+\frac{3}{4}\)

\(\Leftrightarrow\frac{7}{12}x=\frac{37}{12}\)

\(\Leftrightarrow x=\frac{37}{12}\div\frac{7}{12}\)

\(\Rightarrow x=\frac{37}{7}\)

Answer 2

\(\frac{x-1}{3}+\frac{x-3}{4}=2\)

\(\Leftrightarrow\frac{4\left(x-1\right)}{12}+\frac{3\left(x-3\right)}{12}=\frac{24}{12}\)

\(\Leftrightarrow4\left(x-1\right)+3\left(x-3\right)=24\)

\(\Leftrightarrow4x-4+3x-9=24\)

\(\Leftrightarrow7x-13=24\)

\(\Leftrightarrow7x=37\)

\(\Leftrightarrow x=\frac{37}{7}\)

Answer 3

\(\frac{x-1}{3}+\frac{x-3}{4}=2\Leftrightarrow\frac{4\left(x-1\right)}{12}+\frac{3\left(x-3\right)}{12}=\frac{24}{12}\)

Khử mẫu : \(4x-4+3x-9=24\)

\(\Leftrightarrow7x-13=24\Leftrightarrow7x=37\)

\(\Leftrightarrow x=\frac{37}{7}\)Vậy pt có nghiệm là x = 37/7