vì (x-1/2)2=0
x2-1/22=0
x2=1/22
=>x=1/2
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Các câu hỏi tương tự
Bài 1 : tìm x biết
a) ( /x/ - 1/4 ) . ( x2 - 9 ) = 0
b) ( /x/ + 2 ) . ( /x/ - 4 ) = 0
c) ( x2 - 1/4 ) . ( x2 - 1/10 ) = 0
d) ( x + 2 ) . ( x - 3 ) < 0
e) ( x - 1/4 ) . ( x + 1/2 ) > 0
Bài 1 : Tìm x biết
a) ( /x/ - 1/4 ) . ( x2 - 9 ) = 0
b) ( /x/ + 2 ) . ( /x/ - 4 ) = 0
c) ( x2 - 1/4 ) . ( x2 - 1/16 ) = 0
d) ( x + 2 ) . ( x - 3 ) < 0
e) ( x - 1/4 ) . ( x + 1/2 ) > 0
|x+3| + |x-y| =0
|x-1| + (y-2)2 =0
|x-3| + |x-2y+1| =0
|x-2| + |3x .y-5| =0
|x-2| - 3|2-x| =-10
|x-3|+ |x-y+1|=0
|x-1| + (y+5)2020 =0
gia tri x>0 sao cho x^2:(-1/2)^3=-1/2
giá trị x thỏa mãn (x-1/2)^20=0
giá trị x<0 thỏa mãn x^2:(-1/2)^3=-1/2
tìm x
(x-1).(x+3)<0
(2-1).(x+5) >0
(x-5).(x+1/2)>0
(x+1).(x-3/2)<0
a) (x+1).(x-3/2)<0
b) (x-2).(x-1/2)>0
Tìm x biết : x mũ 2 + ( x - 1 ) mũ 2 = 0 , ( x -1 ) . ( x - 5 ) > 0 , ( x + 1 ) . ( x - 2 ) < 0
Tim x, y, z biet
a ) |x-3,5|+ |x+5|=0
b) |x-1| + (y+1)^2 + |z-1|=0
c) ( x-1/3)^2 + (y-2)^2+ (z-1)^2 be hon hoac bang 0
d)(x-z)^2+ (y+x)^2 + (z+1/4)^2 =0
Cac ban giup minh voi minh can gap lam
Tìm x, x thuộc Q:
a) (x +1) * (x - 2) < 0
b) (x - 2) * (x + 2/3) > 0
c) x + 1/2 * (x - 1/3) < 0
x mũ 2-x=0
x mũ 2 +2x=0
x mũ 2-3x=0
3x mũ 2 +4=0
[1/4x-1]+[5/6x-2]-[3/8x+5]-3,5=0