Question

(x-1)/2005 = (3-y)/2000  va x-y=4009. Tìm x; y

Answer 1

Lời giải:

Áp dụng TCDTSBN:

\(\frac{x-1}{2005}=\frac{3-y}{2000}=\frac{x-1+3-y}{2005+2000}=\frac{x-y+2}{4005}=\frac{4009+2}{4005}=\frac{4011}{4005}\)

\(\Rightarrow x-1=\frac{4011}{4005}.2005\Rightarrow x=\frac{536404}{267}\\ 3-y=\frac{4011}{4005}.2000\Rightarrow y\approx -2000\)