(\(x-1\))2 - 16 = - 12
(\(x-1\))2 = - 12 + 16
(\(x-1\))2 = 4
(\(x-1\))2 = 22
\(\left[{}\begin{matrix}x-1=-2\\x-1=2\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=-2+1\\x=2+1\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=-1\\x=3\end{matrix}\right.\)
Vậy \(x\) \(\in\) {-1; 3)
(x - 1)2 - 16 = -12
(x - 1)2 = (-12) + 16
(x - 1)2 = 4
Hay (x - 1)2 = 22
=> x - 1 = 2
=> x = 3
Vậy x = 3