1/4×1/16×1/32=\(\frac{1}{2^2}\)x \(\frac{1}{2^4}\)x \(\frac{1}{2^6}\)=\(\frac{1}{2^{12}}\)
Ta có :
\(\frac{1}{4}.\frac{1}{16}.\frac{1}{32}=\frac{1}{2^2}.\frac{1}{2^4}.\frac{1}{2^5}=\frac{1}{2^{11}}=\frac{1^{11}}{2^{11}}=\left(\frac{1}{2}\right)^{11}\)
Chúc bạn học tốt ~
\(\frac{1}{4}×\frac{1}{16}×\frac{1}{32}=\frac{1}{2^2}×\frac{1}{2^4}×\frac{1}{2^5}=\frac{1}{2^{11}}\)
\(\frac{1}{4}\times\frac{1}{16}\times\frac{1}{32}\)
\(=\frac{1}{4\times16\times32}\)
\(=\frac{1}{2^2\times2^4\times2^5}\)
\(=\frac{1}{2^{11}}\)
\(\frac{1}{4}\times\frac{1}{16}\times\frac{1}{32}\)
\(=\left(\frac{1}{2}\right)^2\times\left(\frac{1}{2}\right)^4\times\left(\frac{1}{2}\right)^5\)
\(=\left(\frac{1}{2}\right)^{2+4+5}\)
\(=\left(\frac{1}{2}\right)^{11}\)