\(\dfrac{3}{2}\times\dfrac{9}{4}\times\dfrac{81}{16}=\dfrac{3}{2}\times\left(\dfrac{3}{2}\right)^2\times\left(\dfrac{3}{2}\right)^4=\left(\dfrac{3}{2}\right)^7\)
\(\left(\dfrac{1}{2}\right)^7\times8\times32\times2^8=\left(\dfrac{1}{2}\right)^7\times2^3\times2^5\times2^8=\left(\dfrac{1}{7}\right)^7\times2^{16}\)
\(\left(-\dfrac{1}{7}\right)^4\times125\times5=\left(-\dfrac{1}{7}\right)^4\times5^3\times5=\left(-\dfrac{1}{7}\right)^4\times5^4\)
\(4\times32:\left(2^3\times\dfrac{1}{16}\right)=2^2\times2^5:2^3:2^{-4}=2^0\)
\(\left(\dfrac{1}{7}\right)^2\times\dfrac{1}{7}\times49=\left(\dfrac{1}{7}\right)^3\times7^3=1^3\)
6, \(\dfrac{3}{2}\times\dfrac{9}{4}\times\dfrac{81}{16}=\dfrac{3}{2}\times\left(\dfrac{3}{2}\right)^2\times\left(\dfrac{3}{2}\right)^4\)
7,\(\left(\dfrac{1}{2}\right)^7\times8\times32\times2^8=\left(\dfrac{1}{2}\right)^7\times2^3\times2^5\times2^8\)
8,\(\left(-\dfrac{1}{7}\right) ^4\times125\times5=\left(\dfrac{1}{7}\right)^4\times5^3\times5\)
9,\(4\times32:\left(2^3\times\dfrac{1}{16}\right)=2^2\times2^5:\left[2^3\times\left(\dfrac{1}{2}\right)^4\right]\)
10, \(\left(\dfrac{1}{7}\right)^2\times\dfrac{1}{7}\times49=\left(\dfrac{1}{7}\right)^2\times\dfrac{1}{7}\times7^2\)
6) \(...=\dfrac{3}{2}.\left(\dfrac{3}{2}\right)^2.\left(\dfrac{3}{2}\right)^4=\left(\dfrac{3}{2}\right)^7\)
7) \(...=2^{-7}.2^3.2^5.2^8=2^9\)
8) \(...=\left(\dfrac{1}{7}\right)^4.5^3.5=\left(\dfrac{1}{7}\right)^4.5^4\)
9) \(...=2^2.2^5:\left(2^3.2^{-4}\right)=2^8\)
10) \(...=\left(\dfrac{1}{7}\right)^3.\left(\dfrac{1}{7}\right)^2=\left(\dfrac{1}{7}\right)^5\)
10)...\(...=7^{-3}.7^2=7^{-1}=\dfrac{1}{7}\)
6, \(\dfrac{3}{2}\) \(\times\) \(\dfrac{9}{4}\) \(\times\) \(\dfrac{81}{16}\)
= \(\dfrac{3.3^2.3^4}{2.2^2.2^4}\)
= \(\dfrac{3^7}{2^7}\)
= (\(\dfrac{3}{2}\))7
7; (\(\dfrac{1}{2}\))7 \(\times\) 8 \(\times\)32 \(\times\) 2\(^8\)
= \(\dfrac{1}{2^7}\) \(\times\) 23 \(\times\) 25 \(\times\) 28
= \(\dfrac{1}{2^7}\) \(\times\) 216
= 29
8, (-\(\dfrac{1}{7}\))4 \(\times\) 125 \(\times\) 5
= \(\dfrac{1}{7^4}\) \(\times\) 53 \(\times\) 5
= \(\dfrac{1}{7^4}\) \(\times\) 54
= (\(\dfrac{5}{7}\))4
9; 4 \(\times\) 32 : (23 \(\times\) \(\dfrac{1}{16}\))
= 22 \(\times\) 25 : \(\dfrac{1}{2}\)
= 22 \(\times\) 25 \(\times\) 2
= 28
10; ( \(\dfrac{1}{7}\))2 \(\times\) \(\dfrac{1}{7}\) \(\times\) 49
= \(\dfrac{1}{7^2}\) \(\times\)72 \(\times\) \(\dfrac{1}{7}\)
= \(\dfrac{1}{7}\)
= 7-1