Đặt \(\frac{a}{b}=\frac{c}{d}=k\Rightarrow\hept{\begin{cases}a=bk\\c=dk\end{cases}}\)
Ta có :
\(\frac{2009a-b}{a}=\frac{2009.bk-b}{bk}=\frac{b.\left(2009k-1\right)}{bk}=\frac{2009k-1}{k}\left(1\right)\)
\(\frac{2009c-d}{c}=\frac{2009dk-d}{dk}=\frac{d.\left(2009k-1\right)}{dk}=\frac{2009k-1}{k}\left(2\right)\)
\(\)Từ ( 1 ) và ( 2 ) => \(\frac{2009a-b}{a}=\frac{2009c-d}{c}\)
=> đpcm
Nhớ cho mk nha
\(\frac{2009a}{a}-\frac{b}{a}=\frac{2009c}{c}-\frac{d}{c}\)
=> \(2009-\frac{b}{d}=2009-\frac{d}{c}\)
Hay: \(2009-\frac{a}{b}=2009-\frac{c}{d}\)
Mà: \(\frac{a}{b}=\frac{c}{d}\)
=>\(\frac{2009a-b}{a}=\frac{2009c-d}{c}\)
Ta có a/b=c/d,Suy ra:b/a=d/c.(1)
Lại có:từ(1) suy ra:2009-b/a=2009-d/c
suy ra:2009a-b/a=2009c-d(d.p.c.m)