a, Ta có: \(n_{CuO}=\dfrac{2,4}{80}=0,03\left(mol\right)\)
PT: \(2Cu+O_2\underrightarrow{t^o}2CuO\)
____0,03_0,015___0,03 (mol)
\(\Rightarrow m_{Cu}=0,03.64=1,92\left(g\right)\)
\(m_{O_2}=0,015.32=0,48\left(g\right)\)
b, \(2KClO_3\underrightarrow{t^o}2KCl+3O_2\)
Theo PT: \(n_{KClO_3}=\dfrac{2}{3}n_{O_2}=0,01\left(mol\right)\Rightarrow m_{KClO_3}=0,01.122,5=1,225\left(g\right)\)