\(\left(x+4\right)\left(3x-6\right)=0\)
\(\Rightarrow\left(x+4\right)\cdot3\cdot\left(x-2\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x+4=0\\x-2=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=-4\\x=2\end{matrix}\right.\)
Vậy: \(x\in\left\{-4;2\right\}\).
(x + 4).(3x - 6) = 0
TH1: x + 4 = 0
x = 0 - 4
x = (-4)
TH2: 3x - 6 = 0
3x = 0 + 6
3x = 6
x = 6 : 3
x = 2
⇒ Vậy x = (-4) hoặc x = 2.