Question

Tinhs tổng S=1x2+2x3+3x4+...+99x100

Answer 1

Đặt A=1.2+2.3+3.4+...+99.100
3A=1.2.3+2.3.(4-1)+3.4.(5-2)+...+99.100.(101-98)
3A=1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+...+99.100.101-98.99.100
3A=99.100.101
A=333300

Answer 2

S = 1.2 + 2.3 + 3.4+.....+99.100

3S=1.2.3+2.3.(4-1) + ..... + 99.100.(101-98)

3S = 1.2.3 + 2.3.4 - 1.2.3 + 99.100.101-98.99.100

3S = 99.100.101 = 999900

S = 999900 : 3  = 333300

Answer 3

333300 

tích nha

Answer 4

Gọi biểu thức trên là A, ta có :

A = 1x2 + 2x3 + 3x4 + 4x5 + ...+ 99x100

A x 3 = 1x2x3 + 2x3x3 + 3x4x3 + 4x5x3 + ... + 99x100x3

A x 3 = 1x2x3 + 2x3x(4-1) + 3x4x(5-2) + 4x5x(6-3) + ... + 99x100x(101-98)

A x 3 = 1x2x3 + 2x3x4 - 1x2x3 + 3x4x5 - 2x3x4 + 4x5x6 - 3x4x5 + ... + 99x100x101 - 98x99x100.

A x 3 = 99x100x101

A = 99x100x101 : 3

A = 333300

Answer 5

333300

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