Question

Tính
e, \(E=\dfrac{4^6.3^4.9^5}{6^{12}}\)                                             f, \(F=\dfrac{2^{13}+2^5}{2^{10}+2^2}\)

g, \(G=\dfrac{21^2.14.125}{35^5.6}\)                                         h, \(H=\dfrac{45^3.20^4.18^2}{180^5}\)

Answer 1

e) \(E=\dfrac{4^6.3^4.9^5}{6^{12}}=\dfrac{2^{12}.3^4.3^{10}}{2^{12}.3^{12}}=\dfrac{3^4}{3^2}=3^2=9\)

f) \(F=\dfrac{2^{13}+2^5}{2^{10}+2^2}=\dfrac{2^3\left(2^{10}+2^2\right)}{2^{10}+2^2}=2^3=8\)

g) \(G=\dfrac{21^2.14.125}{35^5.6}=\dfrac{3^2.7^2.7.2.5^3}{7^5.5^5.2.3}=\dfrac{3}{7^2.5^2}=\dfrac{3}{1225}\)

h) \(H=\dfrac{45^3.20^4.18^2}{180^5}=\dfrac{9^3.5^3.5^4.4^4.9^2.2^2}{9^5.4^5.5^5}=5^2=25\)