Question

Tính:

\(\dfrac{3}{12}-\left(\dfrac{6}{12}-\dfrac{3}{10}\right)\)

Answer 1

\(\dfrac{3}{12}-\left(\dfrac{6}{12}-\dfrac{3}{10}\right)=\dfrac{3}{12}-\dfrac{6}{12}+\dfrac{3}{10}=\dfrac{3.5-6.5+3.6}{60}=\dfrac{3}{60}=\dfrac{1}{20}\)

Answer 2

\(\dfrac{3}{12}-\left(\dfrac{6}{12}-\dfrac{3}{10}\right)\)

\(=\dfrac{3}{12}-\dfrac{6}{12}+\dfrac{3}{10}\)

\(=\dfrac{-3}{12}+\dfrac{1}{10}\)

\(=\dfrac{-1}{4}+\dfrac{1}{10}\)

\(=\dfrac{-10}{40}+\dfrac{4}{40}\)

\(=\dfrac{-6}{40}\)

\(=\dfrac{-3}{20}\)

Answer 3

1/20

Answer 4

\(\dfrac{3}{12}-\left(\dfrac{6}{12}-\dfrac{3}{10}\right)\)

\(=\dfrac{3}{12}-\dfrac{6}{12}+\dfrac{3}{10}\)

\(=-\dfrac{3}{12}+\dfrac{3}{10}\)

\(=-\dfrac{15}{60}+\dfrac{18}{60}\)

\(=\dfrac{3}{60}\)\(=\dfrac{1}{20}\)