Question

tính:

B=

\(y=\frac{1+2+2^2+2^3+....+2^{2008}}{1-2^{2009}}\frac{ }{ }\)

Answer 1

2Y=\(\frac{2+2^2+2^3+.......+2^{2009}}{1-2^{2009}}\)

2Y-Y= \(\frac{1-2009}{1-2009}\)

Y=1