B = 1 + 3 + 3^2 + 3^3 + ....+ 3^50
3B= 3+3^2+3^3+3^4+....+3^51
3B-B=(3+3^2+3^3+3^4+....+3^51)-(1+3+3^2+3^3+....+3^50)
2B=3^51-1
=> B=(3^51-1) : 2
Ủng hộ mik nhé !
B=\(1+3+3^2+...+3^{50}\)
3B=\(3+3^2+...+3^{51}\)
3B-B=\(\left(3+3^2+3^3+...+3^{51}\right)-\left(1+3+3^2+...+3^{50}\right)\)
2B=2+3^51
B=\(\frac{2+3^{51}}{2}\)
\(3B=3+3^2+3^3+...+3^{51}\)
\(3B-B=\left(3+3^2+...+3^{51}\right)-\left(1+3+3^2+...+3^{50}\right)\)
\(2B=3^{51}-1\)
\(B=\frac{3^{51}-1}{2}\)