Question

tính

√5.(√3+√2) 

 

(√3−√5)2

(√7−√2).(√7+√2)

(√3+√5)2

(√8+3√7)+(√8−3√7)

Answer 1

\(\sqrt{5}\left(\sqrt{3}+\sqrt{2}\right)=\sqrt{5.3}+\sqrt{5.2}=\sqrt{15}+\sqrt{10}\)

\(2\left(\sqrt{3}-\sqrt{5}\right)=\sqrt{4}\left(\sqrt{3}-\sqrt{5}\right)=\sqrt{4.3}-\sqrt{4.5}=\sqrt{12}-\sqrt{20}\)

\(\left(\sqrt{7}-\sqrt{2}\right)\left(\sqrt{7}+\sqrt{2}\right)=\left(\sqrt{7}\right)^2-\left(\sqrt{2}\right)^2=7-2=5\)

Answer 2

\(2\left(\sqrt{3}+\sqrt{5}\right)=\sqrt{4}\left(\sqrt{3}+\sqrt{5}\right)=\sqrt{4.3}+\sqrt{4.5}=\sqrt{12}+\sqrt{20}\)

\(\left(\sqrt{8}+3\sqrt{7}\right)\left(\sqrt{8}-3\sqrt{7}\right)=\left(\sqrt{8}\right)^2-\left(3\sqrt{7}\right)^2=8-63=-55\)

Answer 3

2√10.5√8.√2210.58.2

Tính

√20.(5√3+√5)20.(53+5)

(3√2+√3)2