Tính tổng
\(\frac{4^7.2^8}{3.2^{15}.16^2-5.2^2.\left(2^{10}\right)^2}\)
cứu mình vơi a:
Tính:
\(\frac{4^7.2^8}{3.2^{15}-16^2-5.2^2.\left(2^{10}\right)^2}\)
B=\(\frac{2^{19}.27^3+15.4^9.9^4}{6^9.2^{10}+12^{10}}\)
C=\(\frac{2^{13}.4^{11}-16^9}{\left(3.2^{17}\right)^2}\)
D=\(\frac{4^7.2^8}{3.2^{15}.16^2-5.2^2.\left(2^{10}\right)^2}\)
Rút Gọn
d, \(\frac{4^7.2^8}{3.2^{15}.16^2-5.2^2.\left(2^{10}\right)^2}\)
nói cách làm nhé ^_^
Tính -2 .2+3.2+5.2+7.2+9.2+11.2+13.2+......+ 103.2+105.2+107.2
Rút gọn Phân số:
1, \(\frac{7.25^{14}.125^3-3.625^9.5}{2.4^2.\left(5^2\right)^{18}}\)
2, \(\frac{4^7.2^8}{3.2^{15}.16^2-5.2.\left(2^{10}\right)^2}\)
tính A=47.28/3.215.162_5.22."210"2
Tinh B = 4^7 . 2^8
3.2^13 .16^2 -5.2^2 .(2^10)^2
tính nhanh:(4^5.10.5^6+25^5.2^8):(2^8.5^4+5^7.2^5)
