Question

tính

1/1.2+1/2.3+1/3.4+.....+1/99.100

Answer 1

\(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{99.100}\)

\(=\frac{2-1}{1.2}+\frac{3-2}{2.3}+\frac{4-3}{3.4}+...+\frac{100-99}{99.100}\)

\(=\frac{2}{1.2}-\frac{1}{1.2}+\frac{3}{2.3}-\frac{2}{2.3}+....+\frac{100}{99.100}-\frac{99}{99.100}\)

\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{99}-\frac{1}{100}\)

\(=1-\frac{1}{100}=\frac{99}{100}\)

Answer 2

1-1/2+1/2-1/3+1/3-1/4+1/4-..........+1/99-1/100=1-1/100=99/100

Answer 3

1/1.2+1/2.3+1/3.4+.......=1/99.100

A=1-1/2+1/2-1/3+....+1/99-1/100

A=1-1/100

A=99/100