\(\frac{3x}{4}=\frac{4y}{5}=\frac{2z}{3}\)
vì \(4\ne5\ne3\)
nên \(\frac{3x}{4}=\frac{4y}{5}=\frac{2z}{3}=0\)
do đó 3x=4y=2z=0 nên x=y=z=0
\(\frac{4}{3x-2y}=\frac{3}{2z-4x}=\frac{2}{4y-3x}\)và x+y-z=-10
Tìm X,Y,Z:
\(\frac{4}{3x-2y}=\frac{3}{2z-4x}=\frac{2}{4y-3z}\) và x+y-z=-10
cho \(\frac{3x-2y}{4}=\frac{2z-4x}{3}=\frac{4y-3x}{2}\)
chứng minh rằng\(\frac{x}{2}=\frac{y}{3}=\frac{z}{4}\)
Tìm x, y, z, biết:
a) \(\frac{2x}{3}=\frac{3y}{4}=\frac{4z}{5}\)và 3x - 4y + 5z = 6
b)\(\frac{x}{2}=\frac{y}{3}=\frac{z}{5}\)và x.y.z = 810
c)\(\frac{3x}{2}=\frac{y}{3}=\frac{z}{4}\)và 9x2 - y2 + 2z2 = 108
d)\(\frac{2}{x-1}=\frac{3}{y-2}=\frac{4}{z-3}\)và 2x + 3y - z
Cho \(\frac{3x-2y}{4}=\frac{2z-4x}{3}=\frac{4y-3z}{2}.\)Chứng minh rằng \(\frac{x}{2}=\frac{y}{3}=\frac{z}{4}\)
cho\(\frac{3x-2y}{4}=\frac{2z-4x}{3}=\frac{4y-3z}{2}\)
cmr:\(\frac{x}{2}=\frac{y}{3}=\frac{z}{4}\)
Cho \(\frac{3x-2y}{4}=\frac{2z-4x}{3}=\frac{4y-3z}{2}.\)CMR \(\frac{x}{2}=\frac{y}{3}=\frac{z}{4}\)
Chứng minh rằng : x/2 = y/3 = z/4
BIết :\(\frac{3x-2y}{4}=\frac{2z-4x}{3}=\frac{4y-3z}{2}\)
Chứng minh: \(\frac{x}{2}=\frac{y}{3}=\frac{z}{4}\)nếu \(\frac{3x-2y}{4}=\frac{2z-4x}{3}=\frac{4y-3z}{2}\)