CO(NH2)2 \(\left\{{}\begin{matrix}\%C=\dfrac{12}{60}.100\%=20\%\\\%O=\dfrac{16}{60}.100\%=26,67\%\\\%N=\dfrac{28}{60}.100\%=46,67\%\\\%H=\dfrac{4}{60}.100\%=6,66\%\end{matrix}\right.\)
2 kg đạm ure \(\Rightarrow m_{CO\left(NH_2\right)_2}=2.\left(100-5\right)\%=1,9\left(kg\right)\)
`=>` \(m_N=46,67\%.1,9=0,88673\left(kg\right)\)